1111Aa RV3012M inverter installation photos
|
06-12-2008, 05:27
Post: #8
|
|||
|
|||
1111Aa RV3012M inverter installation photos
The (2008) LXIs I saw at CCW while I was on my extended service in Riverside have 10 (type 4D) house batteries located in (approximately) the same place as the house battery compartment in the '95 model. Since there are so many batteries, there's no room for the inverters in the same compartment as is the case for the '95. This compartment is just behind the tag axle.Â
The inverters are next to the tool box (as in the 2000 LXI) -- but the cable run is quite probably no more than 12', taking the most direct route. As for cable size, in the June 2008 Bus Conversions magazine, there is a discussion of suitable conductor sizes for 12v systems. With 120 v systems, cable size is generally based on the amp load expected, as the voltage loss due to resistance is usually not a significant factor with 120 v circuits. With 12 v systems, the voltage loss due to resistance is the primary concern as that usually becomes the more important factor before amp load becomes an issue: Here's an excerpt from the chart in the magazine -- note that current and resistance are calculated from a combination of different sources ... they're about 24% lower than the National Electric Code but "slightly" higher than figures from the Radio Amateur's Handbook). AWG    Size (in)     Max Amps    Ohms-per-foot resistance 0000    .53         195        .000051 000     .47         165        .000064 00      .42         145        .000089 0       .37         125        .000102 The size (diameter) is approximate. These are stranded cables, so the size will vary. To figure the loss in voltage, multiply the resistance (ohms per foot) times  the length (in feet) times the current (in amps). Since the maximum amps a 2500 watt inverter uses is about 20 amps at 120 v, the 12 v draw (well, actually 14v for a fully charged battery) would be about 180 amps. That suggests 0000 AWG wire as being the minimum size to use. (is there 5/0 wire available?) Over a distance of 12 ft, the voltage drop would be .000051* 12 (ft) * 180 = .11016 or about 11% of the voltage. That's about 1.5 volts. As the voltage drops, the inverter will require more amps to output the required 120 vac amps and the wires will soon overheat and exceed the safe margin for the cable. Pete Masterson '95 Blue Bird Wanderlodge WBDA 42 El Sobrante CA "aeonix1@mac.com" On Jun 11, 2008, at 9:45 PM, David Brady wrote: Kurt, |
|||
« Next Oldest | Next Newest »
|
User(s) browsing this thread: 3 Guest(s)